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5n^2-40n-9600=0
a = 5; b = -40; c = -9600;
Δ = b2-4ac
Δ = -402-4·5·(-9600)
Δ = 193600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{193600}=440$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-440}{2*5}=\frac{-400}{10} =-40 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+440}{2*5}=\frac{480}{10} =48 $
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